25 lines
484 B
Python
25 lines
484 B
Python
#!/usr/bin/env python3
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# The series, 1^1 + 2^2 + 3^3 + ... + 10^10 = 10405071317.
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#
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# Find the last ten digits of the series, 1^1 + 2^2 + 3^3 + ... + 1000^1000.
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from projecteuler import timing
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@timing
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def p048() -> None:
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_sum = 0
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# Simply calculate the sum of the powers
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for i in range(1, 1001):
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power = i ** i
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_sum = _sum + power
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print('Project Euler, Problem 48')
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print(f'Answer: {str(_sum)[-10:]}')
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if __name__ == '__main__':
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p048()
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