39 lines
1010 B
Python
39 lines
1010 B
Python
#!/usr/bin/python3
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# The sum of the squares of the first ten natural numbers is,
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#
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# 1^2 + 2^2 + ... + 10^2 = 385
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#
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# The square of the sum of the first ten natural numbers is,
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#
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# (1 + 2 + ... + 10)^2 = 55^2 = 3025
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#
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# Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
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#
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# Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
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from timeit import default_timer
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def main():
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start = default_timer()
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sum_squares = 0
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square_sum = 0
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# Straightforward brute-force approach.
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for i in range(1, 101):
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sum_squares = sum_squares + i * i
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square_sum = square_sum + i
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square_sum = square_sum * square_sum
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end = default_timer()
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print('Project Euler, Problem 6')
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print('Answer: {}'.format(square_sum - sum_squares))
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print('Elapsed time: {:.9f} seconds'.format(end - start))
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if __name__ == '__main__':
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main()
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