29 lines
732 B
Python
29 lines
732 B
Python
#!/usr/bin/python3
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# If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
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#
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# Find the sum of all the multiples of 3 or 5 below 1000.
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from timeit import default_timer
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def main():
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start = default_timer()
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sum_ = 0
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# Simple brute-force approach: try every number between 3 and 999,
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# check if it's a multiple of 3 or 5, if yes add it to the total.
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for i in range(3, 1000):
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if i % 3 == 0 or i % 5 == 0:
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sum_ += i
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end = default_timer()
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print('Project Euler, Problem 1')
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print('Answer: {}'.format(sum_))
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print('Elapsed time: {:.9f} seconds'.format(end - start))
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if __name__ == '__main__':
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main()
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