59 lines
1.2 KiB
C
59 lines
1.2 KiB
C
#include <stdio.h>
|
|
#include <stdlib.h>
|
|
#include <time.h>
|
|
|
|
int main(int argc, char **argv)
|
|
{
|
|
int n1_19[19] = {3, 3, 5, 4, 4, 3, 5, 5, 4, 3, 6, 6, 8, 8, 7, 7, 9, 8, 8};
|
|
int n20_90[8] = {6, 6, 5, 5, 5, 7, 6, 6};
|
|
int n100_900[9] = {13, 13, 15, 14, 14, 13, 15, 15, 14};
|
|
int n1000 = 11;
|
|
int sum = 0, i, j;
|
|
double elapsed;
|
|
struct timespec start, end;
|
|
|
|
clock_gettime(CLOCK_MONOTONIC, &start);
|
|
|
|
for(i = 0; i < 19; i++)
|
|
{
|
|
sum += n1_19[i];
|
|
}
|
|
|
|
for(i = 0; i < 8; i++)
|
|
{
|
|
n20_90[i] *= 10;
|
|
for(j = 0; j < 9; j++)
|
|
{
|
|
n20_90[i] += n1_19[j];
|
|
}
|
|
sum += n20_90[i];
|
|
}
|
|
|
|
for(i = 0; i < 9; i++)
|
|
{
|
|
n100_900[i] *= 100;
|
|
for(j = 0; j < 19; j++)
|
|
{
|
|
n100_900[i] += n1_19[j];
|
|
}
|
|
for(j = 0; j < 8; j++)
|
|
{
|
|
n100_900[i] += n20_90[j];
|
|
}
|
|
sum += n100_900[i] - 3;
|
|
}
|
|
|
|
sum += n1000;
|
|
|
|
clock_gettime(CLOCK_MONOTONIC, &end);
|
|
|
|
elapsed = (end.tv_sec - start.tv_sec) + (double)(end.tv_nsec - start.tv_nsec) / 1000000000;
|
|
|
|
printf("Project Euler, Problem 17\n");
|
|
printf("Answer: %d\n", sum);
|
|
|
|
printf("Elapsed time: %.9lf seconds\n", elapsed);
|
|
|
|
return 0;
|
|
}
|