48 lines
1.0 KiB
C
48 lines
1.0 KiB
C
/* The series, 1^1 + 2^2 + 3^3 + ... + 10^10 = 10405071317.
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*
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* Find the last ten digits of the series, 1^1 + 2^2 + 3^3 + ... + 1000^1000.*/
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#include <stdio.h>
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#include <stdlib.h>
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#include <string.h>
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#include <time.h>
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#include <gmp.h>
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#define _POSIX_C_SOURCE 199309L
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int main(int argc, char **argv)
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{
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int i;
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double elapsed;
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struct timespec start, end;
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mpz_t power, sum;
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char *res;
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clock_gettime(CLOCK_MONOTONIC, &start);
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mpz_init_set_ui(sum, 0);
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mpz_init(power);
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/* Simply calculate the sum of the powers using the GMP Library.*/
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for(i = 1; i <= 1000; i++)
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{
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mpz_ui_pow_ui(power, i, i);
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mpz_add(sum, sum, power);
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}
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res = mpz_get_str(NULL, 10, sum);
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mpz_clears(power, sum, NULL);
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clock_gettime(CLOCK_MONOTONIC, &end);
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elapsed = (end.tv_sec - start.tv_sec) + (double)(end.tv_nsec - start.tv_nsec) / 1000000000;
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printf("Project Euler, Problem 48\n");
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printf("Answer: %s\n", res+strlen(res)-10);
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printf("Elapsed time: %.9lf seconds\n", elapsed);
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return 0;
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}
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