Code style improvement
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-- If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
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--
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-- Find the sum of all the multiples of 3 or 5 below 1000.
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sumMultiples :: (Integral n) => n
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sumMultiples :: Integer
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sumMultiples = sum(filter p [ n | n <- [1..999] ])
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where p n = n `mod` 3 == 0 || n `mod` 5 == 0
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main :: IO ()
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main = do
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let result = sumMultiples
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putStrLn $ "Project Euler, Problem 1\n"
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