Clean code

C/p051.c

@@ -54,7 +54,7 @@ int main(int argc, char **argv)
    }
 
    free(primes);
-   
+
    clock_gettime(CLOCK_MONOTONIC, &end);
 
    elapsed = (end.tv_sec - start.tv_sec) + (double)(end.tv_nsec - start.tv_nsec) / 1000000000;

C/p053.c

@@ -61,7 +61,7 @@ int main(int argc, char **argv)
 
    printf("Project Euler, Problem 53\n");
    printf("Answer: %d\n", count);
-   
+
    printf("Elapsed time: %.9lf seconds\n", elapsed);
 
    return 0;

C/p055.c

@@ -57,7 +57,7 @@ int main(int argc, char **argv)
 
    printf("Project Euler, Problem 55\n");
    printf("Answer: %d\n", count);
-   
+
    printf("Elapsed time: %.9lf seconds\n", elapsed);
 
    return 0;
@@ -75,7 +75,7 @@ int is_lychrel(mpz_t n)
    for(i = 0; i < 50; i++)
    {
       mpz_set_ui(reverse, 0);
-    
+
       /* Find the reverse of the given number.*/ 
       while(mpz_cmp_ui(tmp, 0) > 0)
       {

C/p056.c

@@ -43,7 +43,7 @@ int main(int argc, char **argv)
 
    printf("Project Euler, Problem 56\n");
    printf("Answer: %d\n", max);
-   
+
    printf("Elapsed time: %.9lf seconds\n", elapsed);
 
    return 0;

C/p057.c

@@ -56,7 +56,7 @@ int main(int argc, char **argv)
 
    printf("Project Euler, Problem 57\n");
    printf("Answer: %d\n", count);
-   
+
    printf("Elapsed time: %.9lf seconds\n", elapsed);
 
    return 0;

C/p058.c

@@ -55,7 +55,7 @@ int main(int argc, char **argv)
       {
          count++;
       }
-      
+
       i += step;
       ratio = (double)count / diag;
 

C/p060.c

@@ -13,7 +13,7 @@
 #define N 10000
 
 int cat(int i, int j);
-   
+
 int *primes;
 
 int main(int argc, char **argv)
@@ -94,7 +94,7 @@ int main(int argc, char **argv)
 
    printf("Project Euler, Problem 60\n");
    printf("Answer: %d\n", n);
-   
+
    printf("Elapsed time: %.9lf seconds\n", elapsed);
 
    return 0;