Correct problem 9 solution
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42
C/p009.c
42
C/p009.c
@ -11,10 +11,11 @@
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#include <stdio.h>
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#include <stdlib.h>
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#include <time.h>
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#include "projecteuler.h"
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int main(int argc, char **argv)
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{
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int a, b, c, m, n, found = 0;
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int a, b, c, tmpa, tmpb, tmpc, i, m, n, found = 0;
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double elapsed;
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struct timespec start, end;
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@ -24,16 +25,39 @@ int main(int argc, char **argv)
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* Euclid's formula, until the one where a+b+c=1000 is found.*/
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for(m = 2; found == 0; m++)
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{
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for(n = 1; n < m; n++)
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for(n = 1; n < m && !found; n++)
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{
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a = m * m - n * n;
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b = 2 * m * n;
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c = m * m + n * n;
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if(a + b + c == 1000)
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if(gcd(m, n) == 1 && (m % 2 == 0 && n % 2 != 0 || m % 2 != 0 && n % 2 == 0))
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{
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found = 1;
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break;
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a = m * m - n * n;
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b = 2 * m * n;
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c = m * m + n * n;
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if(a + b + c == 1000)
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{
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found = 1;
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break;
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}
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i = 2;
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do
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{
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tmpa = a * i;
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tmpb = b * i;
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tmpc = c * i;
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if(tmpa + tmpb + tmpc == 1000)
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{
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a = tmpa;
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b = tmpb;
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c = tmpc;
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found = 1;
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break;
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}
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i++;
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}while(tmpa + tmpb + tmpc < 1000);
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}
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}
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}
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@ -10,6 +10,8 @@
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#
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# Find the product abc.
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from math import gcd
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from timeit import default_timer
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def main():
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@ -23,14 +25,37 @@ def main():
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# Euclid's formula, until the one where a+b+c=1000 is found.
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while not found:
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for n in range(1, m):
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a = m * m - n * n
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b = 2 * m * n
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c = m * m + n * n
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if a + b + c == 1000:
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found = 1
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if found == 1:
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break
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if gcd(m, n) == 1 and (m % 2 == 0 and n % 2 != 0 or m % 2 != 0 and n % 2 == 0):
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a = m * m - n * n
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b = 2 * m * n
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c = m * m + n * n
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if a + b + c == 1000:
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found = 1
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break
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i = 2
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while True:
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tmpa = a * i
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tmpb = b * i
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tmpc = c * i
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if tmpa + tmpb + tmpc == 1000:
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a = tmpa
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b = tmpb
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c = tmpc
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found = 1
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break
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if tmpa + tmpb + tmpc > 1000:
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break
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i = i + 1
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m = m + 1
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end = default_timer()
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